[PHP] Simple Image Upload

[Gyanu]

PHP Code:

<?php

if (isset($_POST["submit"]))
 {
  $uploadpath = "Images/";
  $uploadpath = $uploadpath.basename($_FILES["imgfile"]["name"]);
  if (!move_uploaded_file($_FILES["imgfile"]["tmp_name"], $uploadpath))
   die("There was an error uploading the file, please try again!");
  $image_name = "Images/".$_FILES["imgfile"]["name"];
  list($width,$height) = getimagesize($image_name);
  $new_image_name = "Images/thumb_".$_FILES["imgfile"]["name"];
  if ($width > $height)
   {
    $ratio = (250/$width);
    $new_width = round($width*$ratio);
    $new_height = round($height*$ratio);
   }
  else
   {
    $ratio = (250/$height);
    $new_width = round($width*$ratio);
    $new_height = round($height*$ratio);
   }
  $image_p = imagecreatetruecolor($new_width,$new_height);
$img_ext = $_FILES['imgfile']['type'];
if (img_ext == "image/jpg" || img_ext == "image/jpeg") {
$image = imagecreatefromjpg($image_name);
} else if ($img_ext == "image/png") {
$image = imagecreatefrompng($image_name);
} else if ($img_ext == "image/gif") {
$image = imagecreatefromgif($image_name);
} else {
die('this is no valid image resource');
}

imagecopyresampled($image_p,$image,0,0,0,0,$new_width,$new_height,$width,$height);
imagejpeg($image_p,$new_image_name,100);
   echo("Image uploaded!");
 }

echo <<<TEXT
<form method="post" enctype="multipart/form-data">
<h1>Image Uploading</h1>
Please select a picture to upload:<br />
<input type="file" name="imgfile" />
<br />
<input type="submit" name="submit" value="Add Image" />
</form>
TEXT;

?>