PHP date()

[jon123]

I am really struggling with this code below. Anyone help?
I don't understand why it isn't working! I can usually sort any php issues but the code below throws a wobbly.

The code explained:
I have a date that i want to insert into mysql but i want to add days to it beforehand. First I need to convert it into US date (y-m.d) as opposed to (d-m-y) then add the extra days

PHP Code:

//$input1 is the european date carried over from the form
list ($day, $month, $year) = split ("-", $input1);
$remdate = $year."-".$month."-".$day;
$added=strtotime($remdate); 
//$adv is the extra days to add
$outdat=$added + (60*60*24*$adv);
$outdate=date('Y-m-d', $outdat); 


$outdate is giving me the timestamp not the mysql date format.
$outdat and $remdate echo out correctly so the form info is being passed to the script

Can't understand why it isn't though!

[jon123]

umm, that's strange! it now works.
I received an email saying my login script wasn't working either but now ok.
Server glitch?
Anyway doesn't matter as it now works as it should.

[kev woodman]

Glad it's sorted mate

Couldn't you have used:

PHP Code:

$outdate = date("Ymd",strtotime($adv,$added); 


to replace the last two lines?

[jon123]

Hi Kev,
No because yours uses todays date, mine uses various. Plus adding $adv any other way that converting to seconds first just won't work. It seems to not move the month 'up' when days exceed total for month.

It is probably me but yes you are right, it certainly could be condensed for 'cleaner coding'. This bit is beyond me i'm afraid.

[kev woodman]

I'm unlikely to ever get accused of producing clean code In fact one of my big jobs in the autumn is likely to be refactoring a load of old code before it chokes an entire server.

[jon123]

Originally Posted by kev woodman

I'm unlikely to ever get accused of producing clean code In fact one of my big jobs in the autumn is likely to be refactoring a load of old code before it chokes an entire server.

...lol

my 'Hello World' script could do that.